Where is ... (ellipsis) supposed to be placed in a C++ parameter pack expansion? Inside or outside of the parenthesis for std::forward?

I am new to C++ parameter pack expansion, and I have been confused about the position of ... (ellipsis) for a long time, eg:

template <typename... Args> 
void func(Args&&... args) {
    // ...
    std::forward<Args>(args)...;
    // ...
}

Why isn't there std::forward<Args>(args...)? What is the rule I should follow?

Check out https://en.cppreference.com/w/cpp/language/parameter_pack, particularly the "Pack expansion" section.

Basically, the "..." in the pack expansion is almost like a macro: it creates more source code, in a way. Whatever is before the "..." just gets repeated for each argument (and the pack-name replaced with said argument), so something like func(args...) would be expanded as "func(a, b, c)", while func(args)... would turn into "func(a), func(b), func(c)".

std::forward just takes one argument and produces one forwarded item: func(std::forward(args)...) will turn into a list of individual forwards: func(std::forward(a), std::forward(b), std::forward(c)). So, it takes a list of arguments, and produces a list of forwarded arguments