Here is my Ruby 3.2 code:
puts (1 and 0)
puts (1 and 0 and 1)
It prints 0 and then 1 (I'm expecting 0 in both cases). Can someone explain, why?
First of all, and and or have very low precedence and are intended for control flow, e.g.
do_this or exit
(assuming do_this will return a truthy result upon success)
For boolean operations, you should use && and || instead.
Next, in Ruby there are two falsy values: false and nil. Every other value is considered truthy, including 0.
You might be looking for:
true && false
#=> false
true && false && true
#=> false
true && true && true
#=> true
If you are working with 1 and 0, bit operations might be useful: (see Integer#&)
1 & 0
#=> 0
1 & 0 & 1
#=> 0
1 & 1 & 1
#=> 1