I have written a C++20's concept myrequirement
:
template<typename T>
concept myrequirement= requires(T s)
{
{ s.type() } -> std::same_as<uint8_t>;
};
enum MyType
{
TYPE1,
TYPE2,
TYPE3,
};
So my users can write unamed structures that will satisfy this requirement like so:
struct
{
static constexpr uint8_t type() { return TYPE1;}
} foo;
struct
{
static constexpr uint8_t type() { return TYPE2;}
} bar;
struct
{
static constexpr uint8_t type() { return TYPE3;}
} baz;
I want the users to be able to retrieve the right unamed structure depending on their type field like so :
auto my_struct = get_instance<TYPE1>();
I thought I could use c++'s pack parameters to be able to write something like this:
template<uint8_t type, myrequirement... StructTypes>
constexpr auto& get_instance_amongst(const StructTypes&... structs)
{
// how do we do this ?
}
template<uint8_t type>
constexpr auto& get_instance()
{
return get_instance_amongst(foo, bar, baz);
}
I've tried quite a lot of code but nothing seems to compile... Is there anything close to this possible ? With fold expression maybe ?
For simple cases like that, you might hardcode the reversal mapping:
template <uint8_t type>
auto& get_instance()
{
if constexpr (type == TYPE1) { return foo; }
else if constexpr (type == TYPE2) { return bar; }
else if constexpr (type == TYPE3) { return baz; }
else { static_assert(false, "Wrong number"); }
}
If you want to retrieve from the instances instead, you might do:
template<uint8_t type, myrequirement... StructTypes>
auto& get_instance_amongst(const StructTypes&... structs)
{
constexpr bool matchTypes[] = {(StructTypes::type() == type)...};
constexpr auto index = std::distance(std::begin(matchTypes), std::ranges::find(matchTypes, true));
return std::get<index>(std::tie(structs...));
}
template<uint8_t type>
auto& get_instance()
{
return get_instance_amongst<type>(foo, bar, baz);
}