Is it possible to use using with a template class without specifying its template parameters straight away?
#include <array>
using MyArray = std::array<int, 5>;
using MyArrayT = std::array; // error: missing template arguments after 'std::array'
int main() {
MyArray myArray1;
MyArrayT<char, 10> myArray2;
}
P.S.: Without using preprocessor tricks...
You cannot do it like that because a "normal" type alias (using statement) is aliasing a concrete type with a new name, and std::array is not a concrete type.
But you can make the type alias itself templated (syntax (2)):
#include <cstddef> // for std::size_t
#include <array>
template <typename T, std::size_t N>
using MyArrayT = std::array<T, N>;
Then use it like you attempted:
MyArrayT<char, 10> myArray2;