Reading space separated integers in mips assembler

I want to read space separated integers in mips assembler. I currently do:

li $v0, 5
syscall
move $t4, $v0

In a loop but it requires to make input with endline. I want to just put many space separated integers and make it read them. How can I do it?

I had this problem and I solved it using the following function:

get_integer:
    li $t1, 10 # t1 = newLine (in ascii)
    li $t0, 32 # t0 = space (in ascii)
    li $v1, 0 # v1 = 0

    read_int_loop:
        li $v0, 12 # Read next char
        syscall

        beq $v0, $t0, read_int_done # if new character == space, end loop
        beq $v0, $t1, read_int_done # if new character == newLine, end loop

        addi $v0, $v0, -48 # Convert ascii to int
        sll $t2, $v1, 3    # t2 = v1 * 8
        sll $v1, $v1, 1    # v1 *= 2
        add $v1, $v1, $t2  # v1 += t2 -> original v1 *= 10
        add $v1, $v1, $v0  # v1 += v0 -> output =  original v1 * 10 + v0

        j read_int_loop    # loop

    read_int_done:
        jr $ra # return (v1)

What this function does is:

• Read the input character by character
• Convert each character to integer
• Multiply the character by 10
• Add the next character to the product

This process ends when either a white space or a new line is entered.

And of course, the function can be called with jal to substitute the regular integer input way that OP has mentioned.