Python function change behaviour depending on type of argument

I'm playing around with OOP in Python, and I have something like this:

class Person:
    def __init__(self,name, age):
        self.name = name
        self.age = age
        self.hobbies = []

    def __add__(self,hobby):
        self.hobbies.append(hobby)
        return self 

    def get_hobbies(self):
        print(self.hobbies)

tom = Person("Tom", 25) 
tom = tom + "Skiing"

tom.get_hobbies()
##["Skiing"]

Is it possible to do something to the __add__ function so that if the hobby parameter is a list, it adds the elements to the hobbies list?

tom = tom + ["cooking", "swimming"]
tom.get_hobbies()
##["Skiing","cooking","swimming"]
##instead of ["Skiing", ["cooking","swimming"]]

I would suggest you to use a bit of typing, to manage if the dunder method is going to accept a list a string, or raise an error if you try to feed it with something else.

from typing import Union

class Person:
    def __init__(self, name: str, age: int) -> None:
        self.name = name
        self.age = age
        self.hobbies: list[str] = []

    def __add__(self, hobby: Union[str, list[str]]) -> "Person":
        if isinstance(hobby, str):
            self.hobbies.append(hobby)
        elif isinstance(hobby, list) and all(isinstance(h, str) for h in hobby):
            self.hobbies.extend(hobby)
        else:
            raise TypeError(
                f"Unsupported operand type for +: 'Person' and '{type(hobby).__name__}' "
                "(expected str or list[str])"
            )
        return self  # allows chaining

    def get_hobbies(self) -> None:
        print(self.hobbies)