When defining a Future as follows:
Future<HttpRequest> httpRequest = HttpRequest.request(url,
method: method, requestHeaders: requestHeaders);
I want to handle a timeout after 5 secondes. I'm writing my code like this :
httpRequest.timeout(const Duration (seconds:5),onTimeout : _onTimeout());
Where my timeout function is :
_onTimeout() => print("Time Out occurs");
According to the Future timeout() method documentation , If onTimeout
is omitted, a timeout will cause the returned future to complete with a TimeoutException
. But With my code , my method _onTimeout()
is properly called (but immediately, not after 5 seconds) and I always get a
TimeException after 5 seconds... (TimeoutException after 0:00:05.000000: Future not completed )
Am I missing something ?
Change this line
httpRequest.timeout(const Duration (seconds:5),onTimeout : _onTimeout());
to
httpRequest.timeout(const Duration (seconds:5),onTimeout : () => _onTimeout());
or just pass a reference to the function (without the ()
)
httpRequest.timeout(const Duration (seconds:5),onTimeout : _onTimeout);
This way the closure that calls _onTimeout()
will be passed to timeout()
.
In the former code the result of the _onTimeout()
call will be passed to timeout()