I'm trying to find the best way to solve the question: "Use Range, Reverse and Join to create {3, 2, 1, 4, 3, 2, 1, 5, 4, 3, 2, 1}
"
So basically the given lists are {1, 2, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3}
.
I could easily solve this question but wanted to know if there is a better way (more efficient) than what i've come up with.:
My Solutions:
In[136]:= Join[ Reverse[Range[3]], Reverse[Range[4]], Reverse[Range[5]] ]
In[141]:= Reverse[Join[ Range[5], Range[4], Range[3] ]]
given lists: {1, 2, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3}
, where you have to use the functions Range, Reverse and Join to create the expected output:
{3, 2, 1, 4, 3, 2, 1, 5, 4, 3, 2, 1}
My solution will not be efficient if there were to be 100 lists instead of three.
Thanks in advance for the help
RUNNING EACH ELEMENT OF A LIST THROUGH A FUNCTION:
listA = {}
Function[x, listA = Join[listA, x]] /@ {Range[5], Range[4], Range[3]}
listB = Reverse[listA]
Clear[listA]
output:
result -> listB: {3, 2, 1, 4, 3, 2, 1, 5, 4, 3, 2, 1}