game-theorysimplex

Trouble with scipy linprog simplex


I'm trying to solve a zero-sum game finding the optimal probability distribution for player I. To do so I'm using scipy linprog simplex method.

I've seen an example, I need to transform this game :

G=np.array([
[ 0  2 -3  0]
[-2  0  0  3]
[ 3  0  0 -4]
[ 0 -3  4  0]])

into this linear optimization problem:

Maximize           z
Subject to:               2*x2 - 3*x3        + z <= 0
                  -2*x1 +             + 3*x4 + z <= 0
                   3*x1 +             - 4*x4 + z <= 0
                        - 3*x2 + 4*x3        + z <= 0
with              x1 + x2 + x3 + x4 = 1

Here's my actual code:

def simplex(G):
    (n,m) = np.shape(G)

    A_ub = np.transpose(G)
    # we add an artificial variable to maximize, present in all inequalities
    A_ub = np.append(A_ub, np.ones((m,1)), axis = 1)
    # all inequalities should be inferior to 0
    b_ub = np.zeros(m)

    # the sum of all variables except the artificial one should be equal to one
    A_eq = np.ones((1,n+1))
    A_eq[0][n] = 0
    b_eq = np.ones(1)

    c = np.zeros(n + 1)
    # -1 to maximize the artificial variable we're going to add
    c[n] = -1

    res = linprog(c, A_ub=A_ub, b_ub=b_ub, A_eq=A_eq, b_eq=b_eq, bounds=(0,None))

    return (res.x[:-1], res.fun)

Here's the distribution I get : [5.87042987e-01 1.77606350e-10 2.79082859e-10 4.12957014e-01] which does sum up to 1, but I expect [0 0.6 0.4 0]

I'm trying on a larger game with 6 or 7 lines (and so variables) and it doesn't even sum up to 1.. What did I do wrong ?

Thanks for any help you could provide.


Solution

  • I haven't updated the post since I found a solution. I recommend not using Scipy linprog function, it's badly documented if you don't know much about linear programming, and I found it to be unprecise and inconsistent on numerous examples (and I did try adding a negative sign at that time, as suggested by oyamad).

    I switched to the PuLP python library, and had no problem having consistent results from the get-go.