How do I display a resource property image in <Image>?

I'm trying to display an image I have saved as a resource under the properties category. This property however returns a byte[] which can't be displayed by <Image> since it can't convert it to ImageSource. The code looks like this:

public byte[] MyImage = Properties.ImageResources.MyImage

but plugging MyImage into

<Image Source="{x:Bind MyImage}"

gives me a conversion error as described above.

I've already tried converting the image to a bitmap to display this instead, but I got the very same error. I've read alot about something like

bitmapImage.BeginInit();
bitmapImage.StreamSource = memory;
bitmapImage.CacheOption = BitmapCacheOption.OnLoad;
bitmapImage.EndInit();

but then it tells me it can't resolve any of the BitmapImage Functions -> BeginInit, EndInit, StreamSource and CacheOption.

I've searched far and wide but they all end in this BeginInit() and EndInit() function which do not exist for me.

Thanks to the help of EldHasp I've found a way to make the images appear.

I have created a data binding converter class that implements the IValueConverter interface:

public class ByteArrayToBitmapImageConverter : IValueConverter
{
    public object? Convert(object value, Type targetType, object parameter, string language)
    {
        if (value is not byte[])
        {
            return null;
        }

        using var ms = new InMemoryRandomAccessStream();
        using (var writer = new DataWriter(ms.GetOutputStreamAt(0)))
        {
            writer.WriteBytes((byte[])value);
            writer.StoreAsync().GetResults();
        }

        var image = new BitmapImage();
        image.SetSource(ms);
        return image;
    }

    public object ConvertBack(object value, Type targetType, object parameter, string language) => throw new NotImplementedException();
}

Or shorter:

public object Convert(
    object value, Type targetType, object parameter, string language)
{
    BitmapImage image = null;

    if (value is byte[] buffer)
    {
        using var ms = new MemoryStream(buffer);
        image = new BitmapImage();
        image.SetSource(ms.AsRandomAccessStream());
    }

    return image;
}

It would be used in XAML e.g. like shown below, when MyImage is a public property of the object in the DataContext of the Grid:

<Grid>
    <Grid.Resources>
        <local:ByteArrayToBitmapImageConverter x:Key="ImageConverter"/>
    </Grid.Resources>

    <Image Source="{Binding MyImage, Converter={StaticResource ImageConverter}}"/>
</Grid>