I am currently using SPIM (QTSpim) to learn about MIPS. I had a few questions regarding the SPIM commands and how they work.
1) As far as I know, MIPS usually uses 16 bits to display values, but why do the registers in QTSpim only have 8 bits?
2) For register $11(t3), the original value was 10. After the machine performs a [sra $11, $11, 2] instruction, the value changes from 10 to 4. How does this happen? How are 2 positions shifted right when 10 is only 2 bits?
Thank you.
1) Not sure where you got that idea. QtSpim simulates a MIPS32-based machine, so the general-purpose registers are 32-bit.
2) 10 hexadecimal is 10000 binary. Shift that right by two and you get 100 binary, which is 4 decimal. You can also think of it as 16 decimal divided by 4, since sra
by N
bits is a (signed) division by 2^N
.